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irinina [24]
2 years ago
9

1" title="\left(\sqrt{3}+4\right)\left(1+\sqrt{3}\right)" alt="\left(\sqrt{3}+4\right)\left(1+\sqrt{3}\right)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
kirza4 [7]2 years ago
4 0

Answer:

\huge\boxed{\sf 7 + 5\sqrt{3} }

Step-by-step explanation:

(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3}  \\\\= 7 + \sqrt{3}  + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0
3 years ago
Help Pls Asap!! Dont really understand the question
PolarNik [594]

Answer: B (the lower one)

Step-by-step explanation:

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2y = -x + 4

y = -1/2x + 2

It is B since the y intercept for that graph is 2.

8 0
2 years ago
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A certain brand of golf balls comes in packs of 24. Each pack has three yellow golf balls in it. Willam orders 360 golf balls on
iogann1982 [59]

Start by taking the total number of golf balls, 360, and dividing it by how many golf balls come in each pack, to find the number of packs.


360 ÷ 24 = 15


So there are 15 packs, each with 3 yellow golf balls.


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Meaning 45 of the golf balls would be yellow



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For |5x|, we have

\dfrac1{1-5x}=\displaystyle\sum_{n\ge0}(5x)^n

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