Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer: B (the lower one)
Step-by-step explanation:
First let's solve for y.
x + 2y = 4
2y = -x + 4
y = -1/2x + 2
It is B since the y intercept for that graph is 2.
Start by taking the total number of golf balls, 360, and dividing it by how many golf balls come in each pack, to find the number of packs.
360 ÷ 24 = 15
So there are 15 packs, each with 3 yellow golf balls.
15 · 3 = 45
Meaning 45 of the golf balls would be yellow
For

, we have

and so

which is, again, only valid for

.
The height of the car at the end of the ride is 4 meters