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choli [55]
3 years ago
10

What is the area of 10 cm 3 cm 7 cm 18 cm

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer: 10 times 3 equals 30 and 7 times 18 equals 126. 126 plus 30 is 156 is the answer

Step-by-step explanation:math

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Which expression is greater than 1/2
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Anything greater than 1/2 can be shown as >1/2
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A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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3 years ago
Suppose that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each
stich3 [128]

We have been given that  you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.            

We will use sum of geometric sequence formula to solve our given problem.

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a = First term of sequence,

r = Common ratio,

n = Number of terms.

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S_{25}=\frac{50\cdot(1-(0.5)^{25})}{1-0.5}

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Answer:

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Step-by-step explanation:

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