No. Say she has a coordinate (3,1)
It can be y=(1/3)x or y=x-2
They can be done either way. So she needs two pairs of values to write an equation.
You look at the coefficient of x.
If the parent function is f(x) = 7^x, there is no horizontal stretch.
If the parent function is f(x) = e^x, then your function is
.. f(x) = 7^x = (e^ln(7))^x = e^(ln(7)*x)
and the horizontal compression factor is ln(7) ≈ 1.946. (The stretch factor is 1/1.946 = 0.514.)
Answer:
2 seconds
Step-by-step explanation:
The formula h = -16t^2 +vt +s gives the vertical height (in feet) at time t (in seconds) for an object with an initial vertical velocity (in ft/s) of v and an initial height (in ft) of s. The problem statement tells us the ball's initial velocity is v=34 and the initial height is s=4.
Then the equation is ...
h = -16t^2 +34t +4
We want to find the value of t when h=8. There will be two solutions, one when the ball is going up, and the other when the ball is coming down. We are interested in the second solution.
8 = -16t^2 +34t +4
16t^2 -34t +4 = 0 . . . . . subtract the right side of the equation to put it into standard form
(16t -2)(t -2) = 0 . . . . . . factor the equation
Solutions are values of t that make the factors zero:
t = 2/16 or t = 2
It takes 2 seconds for the ball to come down to meet Mike's head.
There is no answer, no factors of 27 add up to -18. are you sure the did the math right before this?
Answer:
(-8/7 ; 5/7)
Step-by-step explanation:
5t + 1/2s = 3 - - - (1)
3t - 6s = 9 - - - - - (2)
Multiply (1) by 12 and (2) by 1
Add the result to eliminate s
60t + 6s = 36
3t - 6s = 9
____________
63t = 45
t = 45 / 63
t = 5/7
Put t = 5/7 in either (1) or (2) to obtain the value of s
3(5/7) - 6s = 9
15/7 - 6s = 9
-6s = 9 - 15/7
-6s = (63 - 15)/7
-6s = 48/7
s = 48/7 * - 1/6
s = - 8/7