<h3>Original Equation:</h3>

<h3>Steps:</h3>
<em>*To solve for a variable, isolate the desired variable onto one side.</em>
Firstly, we want to add 1/3 to each side however -5/6 and 1/3 do not share the same denominator, and we want them to have that and we can do that by finding the LCD, or lowest common denominator. To find the LCD, list the multiples of 6 and 3 and the lowest multiple that they share is their LCD. In this case, their LCD is 6. Multiply -1/3 by 2/2:

Now that we have common denominators, add both sides by 2/6:

Next, you want to cancel out 2 to isolate z. Usually, one would divide both sides by 2, however remember that <u>dividing by a number is the same as multiplying by it's reciprocal.</u> To find a number's reciprocal, flip the numerator and denominator around. In this case, since 2 is a <em>whole number</em> this means that the denominator is 1. In this case: 2/1 would become 1/2. Multiply both sides by 1/2:

<h3>Final Answer:</h3>
<u>Your final answer is z = -1/4.</u>
The expression represented by 50 added to half of a number, c is 50 + c/2
<h3>What are expressions?</h3>
Expressions are mathematical statements that are represented by variables, coefficients and operators
<h3>How to translate the algebraic expression?</h3>
The expression is given as
50 added to half of a number, c
half of a number, c means divide c by 2
So, we have
50 added to half of a number, c => 50 added to c/2
Added to means +
So, we have
50 added to half of a number, c => 50 + c/2
Hence, the expression represented by the statement is 50 + c/2
Read more about expressions at
brainly.com/question/22019327
#SPJ1
(3p)(3p) or 3p x 3p. Cause the exponent means 3p times 3p
Answer:
k = -6/35
Step-by-step explanation:
To make the function continuous
kx^2 = x+k
These must be equal where the function is defined for two different intervals
This is at the point x=-6 so let x=-6
k(-6)^2 = -6+k
36k = -6+k
Subtract k from each side
36k-k = -6+k-k
35k = -6
Divide by 35
35k/35 = -6/35
k = -6/35
Answer:

Step-by-step explanation:
The parabola with vertex at point (h,k) is described by the following model:

The equation which satisfies the conditions described above:


The two points are evaluated herein:
x = -6




x = -2




The equation of the translated function is
.