Peter says, "If you subtract 17 from my number and multiply the difference by - 2, the result is

The diameter of a circle is 6 m. Find its area in terms of pi

Pie

<h2>Answer:</h2><h2>9 pi m^2</h2>

Solution,

Diameter=6 m

Radius= 6/2=3m

Area of circle= pi r ^2

 = pi *(3)^2

 = pi*9

 =9 pi metre^2

Hope it helps

Good luck on your assignment

7 0

3 years ago

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I need all of these ASAP please help will mark brainliest

Tcecarenko [31]

Answer:

idk

Step-by-step explanation:

idk

3 0

3 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

3 years ago

Please help me find the surface area:)

Vlad1618 [11]

Answer:

48 im 100 percent sure

7 0

3 years ago

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QUESTIONS ARE DOWN BELOW!!! ALL HELP WILL BE APPRECIATED AND I WILL TRY TO MARK BRAINLIEST (IF I CAN)

dybincka [34]

Answer: 90 and 110

Step-by-step explanation:

7 0

2 years ago

Peter says, "If you subtract 17 from my number and multiply the difference by - 2, the result is - 26."