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lubasha [3.4K]
3 years ago
11

Prove the following relations: 1) (1 - cos²A) (1 + tan²A) = tan²A​

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0

Step-by-step explanation:

(1 - cos²A)(1 + tan²A) = tan²A

1 + tan²A - cos²A - cos²A · tan²A = tan²A

1 + tan²A(1 - cos²A) - cos²A = tan²A

1 - cos²A + tan²A(sin²A) = tan²A

sin²A + tan²A(sin²A) = tan²A

sin²A (1 + tan²A) = tan²A

sin²A (sec²A) = tan²A

sin²A (1/cos²A) = tan²A

(sin²A)/(cos²A) = tan²A

tan²A = tan²A → <u>Proved</u>

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Let pn, n = 0,1,2,..., be the probability that an automobile policyholder will file for n claims in a five-year period. the actu
lara31 [8.8K]
<span>P(1 claim) = p/4
P(2 claims) = (p/4)/4 = p/16

You should see that the distribution follows a geometric series with common ratio 1/4.
Sum geometric = (first term) / (1 - common ratio) = p/(1 - 1/4) = 4p/3

But the sum of all the probabilites must equal 1 ----> 4p/3 = 1 ----> p = 3/4

P(2 or more claims) = 1 - P(0 claims) - P(1 claim) = 1 - 3/4 - 3/16 = 1/16</span>
3 0
3 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

3 0
1 year ago
Evaluate 4 a + 5 b when a=3 and b= -1.2
Basile [38]

Answer:

6

Step-by-step explanation:

Plug the values of a and b into the equation.

4(3) + 5(-1.2)

12 + (-6)

Adding negatives basically means subtracting, so...

12-6 = 6

Therefore your answer is 6

Hope this helps!

3 0
2 years ago
Read 2 more answers
What multiplication equation can you use to check the answer to the problem -32 divided by -4
Naddika [18.5K]

8x-4=-32 so thats an equation that you can use

5 0
3 years ago
Easy Area problem <br><br> Need it fast
Gekata [30.6K]

Answer:

just subtract the area of the rectangle from the area of the carpet

fine I'll do it

Area of a rectangle= lb

Area of a square= a^2

Area of the remaining area= lb - a^2

= (12*4) - (2*2)

= 48-4

= 44 ft^2

5 0
3 years ago
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