<h3>
Answer: No, it is not possible.</h3>
Explanation:
Let the 11 numbers be {a1, a2, ..., a11} such that a1 is the smallest and a11 is the largest. So, a1 < a2 < ... < a11. Furthermore, these numbers are consecutive.
If we add consecutive numbers to get a negative result, then each of the numbers must be negative. So every value in the set {a1, a2, ..., a11} is a negative value which makes it impossible to have a1+a2+...a11 be a positive sum.
Answer:
i don't know if it's right or not cause i can't see a photo but it's median and range
Answer:a
Step-by-step explanation:
Answer:
Im not sure but i think 2 is the answer
Step-by-step explanation:
Answer:
communitive property of multiplication
