P = 2(L + W)
L = W + 5
A = 4P + 2
P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10
A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42
A = L * W
A = W(W + 5)
A = W^2 + 5W
W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0
W - 14 = 0
W = 14 <==
L = W + 5
L = 14 + 5
L = 19 <==
P = 2(19 + 14)
P = 2(33)
P = 66
A = L * W
A = 19 * 14
A = 266
answer : length = 19, width = 14....perimeter = 66....area = 266
![a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6](https://tex.z-dn.net/?f=a%5Ccdot%20a%5Ccdot%20a%3D216%5C%5C%5C%5Ca%5E3%3D216%5Cto%20a%3D%5Csqrt%5B3%5D%7B216%7D%5C%5C%5C%5C%5Cboxed%7Ba%3D6%7D%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20b%5Ccdot%20c%3D52%5C%20%5Ctext%7Bto%20the%20second%20expression%7D%5C%20a%5Ccdot%20b%5Ccdot%20c%3D96%3A%5C%5C%5C%5Cabc96%5C%20%5Cwedge%5C%20bc%3D52%5Cto%20a%2852%29%3D96%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%2052%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B96%7D%7B52%7D%5Cto%20a%3D%5Cdfrac%7B24%7D%7B13%7D%5Cneq6)
a = 6 and a = 24/13 FALSE!!!
<h3>Answer: NO SOLUTION.</h3>
Answer:
1/7
Step-by-step explanation:
The left over fraction is divided among the three children as follows
Given
Left over as 3/7
Number of children 3
Quantity each gets will be 3/7÷3
3/7÷3=3/7*1/3=3/21
By simplyfying the fractions, 3/21 when both the numerator and denominator are divided by 3 we obtain that 3/21=1/7
Therefore, each child geta 1/7
the three numbers are 49,56 and 63.
Answer:
the slope is x or 1x
Step-by-step explanation:
i hope this helps :)
