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Marat540 [252]
3 years ago
13

Have no idea how to do this

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

ans: option C is correct answer

Step-by-step explanation:

follow steps as shown in picture above,

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$12,500 is invested, part at 9% and the rest at 5%. If the interest earned from the amount invested at 9% exceeds the interest e
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$1,538.00

Step-by-step explanation:

4 0
2 years ago
What is the completely factored form of x2 – 16xy 64y2? xy(x – 16 64y) xy(x 16 64y) (x – 8y)(x – 8y) (x 8y)(x 8y)
Alja [10]

The complete factored  form of the quadratic expression is (x-8y)(x-8y)

<h3>Factorizing quadratic expression</h3>

Quadratic expressions are expressions that has a leading degree of 2

Given the expression

x^2 – 16xy + 64y^2

Factorize

x^2 - 8xy - 8xy + 64y^2

Group

(x^2 - 8xy) - (8xy + 64y^2)

x(x-8y) - 8y(x - 8y)

Since (x-8y) is common, hence;

x^2 - 8xy - 8xy + 64y^2 = (x-8y)(x-8y)

The complete factored  form of the quadratic expression is (x-8y)(x-8y)

Learn more on factoring here: brainly.com/question/65494

#SPJ4

3 0
2 years ago
Find the common factor and rewrite. Type your answer in the box. Do not use any spaces.
finlep [7]

Common factor is 4X

Rewriting the term we get: 4X(Y + 2Z)

Step-by-step explanation:

We need to find the common factor of the expression: 4XY + 8XZ

A common factor is the term that is common in all the terms of the expression.

In the given expression the common factor is: 4X because it is common in both terms

4XY + 8XZ

=4X(Y + 2Z)

So, Common factor is 4X

Rewriting the term we get: 4X(Y + 2Z)

Keywords: Factors

Learn more about factors at:

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  • brainly.com/question/2568692

#learnwithBrainly

3 0
4 years ago
Steph makes 90\%90%90, percent of the free throws she attempts. She is going to shoot 333 free throws. Assume that the results o
nikitadnepr [17]

Answer:

0.03

Step-by-step explanation:

khan:)

7 0
3 years ago
Read 2 more answers
Which of the following is a factor of 24x6 − 1029y3?
maria [59]

Answer:

3(48-343y^3)

Step-by-step explanation:

5 0
3 years ago
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