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2 years ago

Oque oque uma mulher tem r$ 30 para dividir entre suas duas filhas que horas são

Mathematics

1 answer:

Alika [10]2 years ago

8 0

Answer:

Ou seja, nesse caso, 15 reais para cada uma, escrevendo de uma maneira mais simples:

" 15 para as duas"

E assim obtemos a resposta, a letra b) 1:45, pois são 15 para as duas.

Step-by-step explanation:

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3+4=4+___? I need help for the math assignment. Thank you.

Montano1993 [528]

Answer:

Step-by-step explanation:

because that's the communicative property

6 0

3 years ago

Read 2 more answers

Olivia goes to Egypt and saw a model of triangle shaped pyramid. She enlarging using a scale factor of 1.2. What will be the per

ivann1987 [24]

If you are talking about the area and perimeter of one of the triangular faces...
8 x 1.2 = 9.6
6 x 1.2 = 7.2

Perimeter = 9.6 + 7.2 + 7.2 = 24
Area = Linear Scale Factor²
1.2² = 1.44
7 x 1.44 = 10.08 (units)²

8 0

3 years ago

I neeed held plzzzzzz

garik1379 [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

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The equation a<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class=

andrezito [222]

Answer:

$\displaystyle \left(\alpha+1\right)\left(\beta + 1\right) = \frac{a+c-b}{a}\:\: \left(\text{ or } 1+\frac{c-b}{a}\right)$

Step-by-step explanation:

We are given the equation:

$ax^2+bx+c=0$

Which has roots α and β.

And we want to express (α + 1)(β + 1) in terms of a, b, and c.

From the quadratic formula, we know that the two solutions to our equation are:

$\displaystyle x_1 = \frac{-b+\sqrt{b^2-4ac}}{2a}\text{ and } x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}$

Let x₁ = α and x₂ = β. Substitute:

$\displaystyle \left(\frac{-b+\sqrt{b^2-4ac}}{2a} + 1\right) \left(\frac{-b-\sqrt{b^2-4ac}}{2a}+1\right)$

Combine fractions:

$\displaystyle =\left(\frac{-b+2a+\sqrt{b^2-4ac}}{2a} \right) \left(\frac{-b+2a-\sqrt{b^2-4ac}}{2a}\right)$

Rewrite:

$\displaystyle = \frac{\left(-b+2a+\sqrt{b^2-4ac}\right)\left(-b+2a-\sqrt{b^2-4ac}\right)}{(2a)(2a)}$

Multiply and group:

$\displaystyle = \frac{((-b+2a)+\sqrt{b^2-4ac})((-b+2a)-\sqrt{b^2-4ac})}{4a^2}$

Difference of two squares:

$\displaystyle = \frac{\overbrace{(-b+2a)^2 - (\sqrt{b^2-4ac})^2}^{(x+y)(x-y)=x^2-y^2}}{4a^2}$

Expand and simplify:

$\displaystyle = \frac{(b^2-4ab+4a^2)-(b^2-4ac)}{4a^2}$

Distribute:

$\displaystyle = \frac{(b^2-4ab+4a^2)+(-b^2+4ac)}{4a^2}$

Cancel like terms:

$\displaystyle = \frac{4a^2+4ac-4ab}{4a^2}$

Factor:

$\displaystyle =\frac{4a(a+c-b)}{4a(a)}$

Cancel. Hence:

$\displaystyle = \frac{a+c-b}{a}\:\: \left(\text{ or } 1+\frac{c-b}{a}\right)$

Therefore:

$\displaystyle \left(\alpha+1\right)\left(\beta + 1\right) = \frac{a+c-b}{a}$

4 0

3 years ago

Nina can ride her bike 63,360 feet in 3,400 seconds, and Sophia can ride her bike 10 miles in 1 hour. What is Nina's rate in mil

avanturin [10]

5,280 feet → 1 mile
63,360 feet → 63,360/5,280 = 12 miles

60 x 60 seconds → 1 hour
3,400 seconds → 3,400/3,600 = 17/18 hours

Nina's rate = 12 miles / (17/18) hours = 12 12/17 miles per hour.

4 0

3 years ago