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Lisa [10]
3 years ago
8

A bakery gave a doughnut to every fifth customer and a cupcake to every twelfth customer. In one day, 8 doughnuts and 3 cupcakes

were given to customers. Which could be the number of customers the bakery had that day?
Mathematics
2 answers:
cricket20 [7]3 years ago
6 0

The bakery had seventy - six(6) customers that day

steposvetlana [31]3 years ago
5 0

Answer:

76

Step-by-step explanation:

Step 1: Identify given information and create 2 equations.

c = # of customers g = given items

1/5c = g (Equation for doughnuts)

1/12c = g (Equation for cupcakes)

Step 2: Substitute in for given items

1/5c = 8

1/5c = 3

Step 3: Use PEMDAS to find c in each equation.

1/5c = 8

*5 *5

c = 40

1/12c = 3

*12 *12

c = 36

Step 4: add customers from both equations

40 + 36 = 76

The bakery had 76 customers that day.

(note I am not a professional and please know that my advice may be incorrect at times)

Hope this helps =)

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P(x >= 13) = P( z > (13 - 14)/1) = P(z > -1) = 1 - P(z < -1) = 1 - 0.1587 = 0.8413

To convert that to percentage, multiply 100, to get 84.13%

3 0
3 years ago
The solution of a+b&gt;−4 is a&gt;−9. What is the value of b?
Lynna [10]

Answer:

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5 0
3 years ago
Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...
svlad2 [7]

Answer:

The required recursive formula is:

a_n=(-3)\times a_{n-1}

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let a_n represents the nth term of the sequence.

This means that:

a_1=6, a_2=-18, a_3=54, a_4=-162,......

As the common ratio is -3.

so,

a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}

Hence, the required recursive formula for the geometric sequence is:

a_n=(-3)\times a_{n-1}

5 0
3 years ago
Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
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and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
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4 0
4 years ago
Approximately how long is a leg of an isosceles right triangle that has a hypotenuse of length 11.31
Lapatulllka [165]

Answer:

Leg of an isosceles right triangle is 7.99 long.

Step-by-step explanation:

Given:

Length of the hypotenuse =11.31

To find:

Length of the leg of an isosceles right triangle =?

Solution:

According to Pythagorean's Theorem, we have

a^2 +b^2 = c^2-----------------------------(1)

Here were are given as isosceles triangle, so the two sides will be of same length

So equation 1 can be rewritten as

a^2 +a^2 = c^2

2a^2 = c^2

Substituting the value of hypotenuse

2a^2 = (11.31)^2

2a^2 = 127.91

a^2 = \frac{127.91}{2}

a^2 =63.955

a = \sqrt{63.955}

a = 7.99

7 0
3 years ago
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