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Lisa [10]
3 years ago
8

A bakery gave a doughnut to every fifth customer and a cupcake to every twelfth customer. In one day, 8 doughnuts and 3 cupcakes

were given to customers. Which could be the number of customers the bakery had that day?
Mathematics
2 answers:
cricket20 [7]3 years ago
6 0

The bakery had seventy - six(6) customers that day

steposvetlana [31]3 years ago
5 0

Answer:

76

Step-by-step explanation:

Step 1: Identify given information and create 2 equations.

c = # of customers g = given items

1/5c = g (Equation for doughnuts)

1/12c = g (Equation for cupcakes)

Step 2: Substitute in for given items

1/5c = 8

1/5c = 3

Step 3: Use PEMDAS to find c in each equation.

1/5c = 8

*5 *5

c = 40

1/12c = 3

*12 *12

c = 36

Step 4: add customers from both equations

40 + 36 = 76

The bakery had 76 customers that day.

(note I am not a professional and please know that my advice may be incorrect at times)

Hope this helps =)

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Franco made a dozen muffins for his party. Upon taking them out of the oven,
Naddik [55]

Answer:

Option B.

Step-by-step explanation:

This question is incomplete; find the complete question with the attachment.

Franco made number of muffins = a dozen

A dozen muffins = 12 muffins

Number of muffins were burned = 2

Remaining muffins = 12 - 2 = 10

Franco served 7 of the remaining non-burned muffins,

Fraction of muffins served = \frac{7}{10}

Remaining muffins = 3

Fraction of remaining muffins = \frac{3}{10}

Fraction of remaining non-burned muffins we can get from,

\frac{10}{10}-\frac{7}{10}=\frac{3}{10}

Option B is the correct equation.

7 0
4 years ago
7. Find the distance between the points (13, 8) and (-12, 6)
Alik [6]

9514 1404 393

Answer:

  √629 ≈ 25.08

Step-by-step explanation:

The distance formula is useful for this.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((-12 -13)² +(6 -8)²) = √(625 +4) = √629 ≈ 25.08

The distance between the points is about 25.08 units.

3 0
2 years ago
A man walks at 60km/ hr. How long does he walks between 9:30 am and 12 noon​
N76 [4]

Answer:

He walks 150 km in 2.5 hours.

Step-by-step explanation:

From 9:30 a.m. to noon, it's 2.5 hours.

distance = speed * time

distance = 60 km/h * 2.5 h

distance = 150 km

Answer: He walks 150 km in 2.5 hours.

3 0
3 years ago
YOU DONT HAVE TO DO ALL IF YOU DONT WANT TO JUST DO WHAT YOU CAN
Vikki [24]

Answer:

(Warning) Not sure this is completley correct but this is just what I did.

Part A

Does the data for Amit’s puppy show a function? Why or why not?

It does show a function because it passes the vertical line test (no two points have the same x value).

Part B

Is the relationship for Amit’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Nonlinear because the line isn’t straight

Part C

Is the relationship between Amit’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because it is gaining weight

Part D

Does the data for Camille’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value

Part E

Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

It is a linear function because the line has no curve, and the line is constant.

Part F

Is the relationship between Camille’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because as the puppy gets older it gains weight.

Part G

Does the data for Olivia’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value. The graph attached ( which shows the data for Camille’s puppy), that each x-value (Weeks) has a unique y-value (Weight in pounds).

Therefore, based on this and keeping in mind the explanation before, you can conclude that the data for Camille’s puppy shows a function.

Part H

Is the relationship for Olivia’s puppy’s weight in terms of time linear or nonlinear? Explain your response

Yes, it linear because it’s a straight line.

Part I

Is the relationship for Olivia’s puppy’s weight in terms of time increasing or decreasing? Explain your response. Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1  14-13= 1. Gaining a pound every week makes the puppy’s weight increase.

Part J

Which two relationships have a y-intercept and a constant rate of change?

They all have y-intercepts and only Olivia and camilles have a constant rate of change.

Part A

To compare the linear functions, you first need to find their equations. For each of the linear functions, write an equation to represent the puppy’s weight in terms of the number of weeks since the person got the puppy.

Linear equation, y=mx+b

Exponential equation, y=a(b)×

Part B

Now you can compare the functions. In each equation, what do the slope and y-intercept represent in terms of the situation?

The y-intercept in the situation is 2/6.

Part C

Whose puppy weighed the most when the person got it? How much did it weigh?

Olivia’s puppy, it weighed 5 pounds

Part D

Whose puppy gained weight the slowest? How much did it gain per week?

Olivia’s puppy gained weight the slowest because it started off with more weight but only gained around 1 pound every week.

Part E

You can also graph the functions to compare them. Using the Edmentum Graphing Tool, graph the two linear functions. Paste a screenshot of the two functions in the space provided. How could you find which puppy had a greater initial weight from the graph? How could you find which puppy gained weight the slowest?

The edmentum graphing tool is opening up I tried it more than once but, the linear graphs would be Camille puppy and olivia's. And I could tell which one had a greater weight by how much they had at week 1 and how much they gained the weeks later. I could find which puppy gained weight the slowest by looking at the weight gained and graphed.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please assist me with the domain and range of graphs​
Sphinxa [80]

Answer:  see below

<u>Step-by-step explanation:</u>

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included <em>(closed dot)</em>, use a bracket [  ]

                      If a value is NOT included <em>(open dot)</em>, use a parenthesis (  )

                     Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

  Range: lowest y-value is 2 (included). highest y-value is 5 (included)

                 D: x = [-4, 3]        R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

  Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, 2]        R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

                 D: x = (-∞, ∞)        R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

  Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

                 D: x = [-2, ∞)        R: y = [-3, ∞)

4 0
3 years ago
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