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2 years ago

Can you solve it of mathematic

Mathematics

1 answer:

Vlada [557]2 years ago

4 0

Answer:

its not so clear but im guessing u r trying to solve the missing spaces so:

Step-by-step explanation:

1st since angle y is VERTICLE (across) from the angle that is 45 degrees angle y is also 45 degress.

and angle z is the same as teh one across from it which is 21

but this is also very odd since teh shape should add up to 360 degrees

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A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h

Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0

2 years ago

A bag contains 4 black tiles, 5 white tiles, and 6 blue tiles. Event A is

Murljashka [212]

Answer:

2/21

Step-by-step explanation:

The question is badly formatted so cannot match the answer choice

Total number of tiles = 4 + 5 + 6 = 15

P(A) = P(drawing a black tile from 15 tiles) = 4/15

After event A, there are 14 tiles left : 3 black, + 5 white + 6 blue

P(B/A) = P(drawing white tile after a black tile has been drawn) = 5/14

P(A and B) = P(A).P(B/A) = 4/15 x 5/14 = 2/21

Note that P(B) = 5/15 since we are talking about independently drawing a white tile from the original stack of tiles

6 0

1 year ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

2 years ago

Is it possible to construct a triangle with side lengths of 15 inches, 17 inches, and 32 inches? Why or why not? (PLEASE HELP ME

dem82 [27]

B because the sum of 2 sides must be GREATER than the 3rd side

6 0

3 years ago

Derek wants to construct a square box stall for each horse that is to be housed in a stable. He wants all of the box stalls to h

ale4655 [162]

The total area of the stable is 20,250 sq. ft.

Let n = total number of box stalls.

Each box stall is a square of length 9 ft.
Total area = 9^2n = 81n ft².
Therefore
81n = 20250
n = 20250/81 = 250

Answer: 250 horses.

8 0

2 years ago