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Lesechka [4]
3 years ago
10

I have a lot of questions to ask on mathematics...so pls help so fastthnx a lot...​

Mathematics
1 answer:
melomori [17]3 years ago
8 0

Answer:

WHAT DO YOU need help with

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Use the table to identify the values of p and q that should be used to factor x^2+9x-10 as (x+p)(x+q)
likoan [24]
X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q  = 10
answer is A.
5 0
3 years ago
Read 2 more answers
Find the solution set. |x| = -4 A. { } B. {-2, 2} C. {-4, 4} D. {-16, 16}
Ray Of Light [21]

Answer:

A. { }

Step-by-step explanation:

Absolute value cannot be less than zero.

-4 < 0

There is no solution for x, ∈, R.  

Hope this helps.

6 0
3 years ago
A cube has a length, width and height of 6 feet. What is the volume in cubic INCHES?
rodikova [14]

Volume of cube = ( side)^3

Side = 6 feet = 6×12 = 72 inches ( 1ft =12 inch)

Vol. = (72)^3 = 72×72×72= 373248 cubic inches

6 0
3 years ago
Find the product:<br> (-9)(-4)
nadya68 [22]

Answer:

36

Step-by-step explanation:

-9*-4=36

3 0
3 years ago
There is a bag filled with 5 blue and 6 red marbles.
Afina-wow [57]

Answer:

The probability of getting two of the same color is 61/121 or about 50.41%.

Step-by-step explanation:

The bag is filled with five blue marbles and six red marbles.

And we want to find the probability of getting two of the same color.

If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.

In other words, we can find the independent probability of each case and add the probabilities together*.

The probability of getting a red marble first is:

\displaystyle P\left(\text{Red}\right)=\frac{6}{11}

Since the marble is replaced, the probability of getting another red is: \displaystyle P\left(\text{Red, Red}\right)=\frac{6}{11}\cdot \frac{6}{11}=\frac{36}{121}

The probability of getting a blue marble first is:

\displaystyle P\left(\text{Blue}\right)=\frac{5}{11}

And the probability of getting another blue is:

\displaystyle P\left(\text{Blue, Blue}\right)=\frac{5}{11}\cdot \frac{5}{11}=\frac{25}{121}

So, the probability of getting two of the same color is:

\displaystyle P(\text{Same})=\frac{36}{121}+\frac{25}{121}=\frac{61}{121}\approx50.41\%

*Note:

We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.

4 0
2 years ago
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