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Bumek [7]
3 years ago
6

The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo

r r ? r = √ π V 3 h r = √ π V 3 h r = √ V h 3 π r is equal to square root of cap v h over 3 pi end root r = √ 3 π V h r is equal to square root of 3 pi over cap v h end root r = √ 3 V π h r = √ 3 V π h
Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: \mathbf{r = \sqrt{\frac{3V}{\pi h}}}

The equation is given as:

\mathbf{V = \frac 13 \pi r^2h}

We start by multiplying both sides by 3

\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}

Rewrite as:

\mathbf{3V= \pi r^2h}

Divide both sides by \mathbf{\pi h}

\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}

Cancel out common factors

\mathbf{\frac{3V}{\pi h}= r^2}

Take square roots of both sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}

Evaluate the right-hand sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= r}

Make r the subject

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Hence, the resulting equating for r is:

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Read more about the subject of formulas at:

brainly.com/question/21866313

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Part A. Find the orthogonal trajectories of the family of curves. (Use C for any needed constant.)x2 + 2y2 = 17k2Part B. Find th
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Answer:

Following are the solution to the question:

Step-by-step explanation:

The objective is to find the orthogonal trajectory of the family curves:

x^2+2y^2=17k^2

The family curves are: x^2 + 2y^2=17k^2  

Differentiate the equation with the respect of x.

\to x^2+2y^2=17k^2 \\\\\to 2x+4y \frac{dy}{dx} =0\\\\\to \frac{dy}{dx} =- \frac{2x}{4y}\\\\\to \frac{dy}{dx} =- \frac{x}{2y}

The negative reciprocal is:

\to \frac{dy}{dx} =-\frac{1}{-\frac{x}{2y}}\\\\\to \frac{dy}{dx} = \frac{2y}{x}

Integration of the above equation:

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Hence, the orthogonal trajectory of the family of the curves x^2 + 2y^2 =17k^2 \ \ is \ \ y=Ax^2

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