All categories

3 years ago

Why is tangent's period 180 degrees?

1 answer:

3 0

In order for tan x = 0, sin x must be = 0
sin x = 0 at 0 degrees and 180 degrees 
so, tan x = 0 at 0, pi 
as for the period being pi, you need to have tan x be negative and positive 
so remember the acronym All students take calculus ( ASTC) for where they are positive. 
tan x is negative in Quadrant II and positive in Quadrant I, since it just repeats after that, the period therefore must be Pi.

You might be interested in

If x= (a^2)/b, which situation would always double the value of x? (1) Doubling the value of a (2) Halving the value of a (3) Do

MariettaO [177]

(4) Halving the value of b

Example #1:
a = 4 , b = 2
x = (4^2) / 2
x = 16 / 2
x = 8
a = 4 , b = 1
x = (4^2) / 1
x = 16 / 1
x = 16

Example #2:
a = 8 , b = 4
x = (8^2) / 4
x = 64 / 4
x = 16
a = 8 , b = 2
x = (8^2) / 2
x = 64 / 2
x = 32

5 0

3 years ago

Prove that SinA×tanA/1-CosA=1+secA

Bad White [126]

answer in the image....

hope it helps!!

3 0

2 years ago

Read 2 more answers

Solve equation step by step... 6x+13y=15

Viktor [21]

13y=15-6x
y=(15-6x)/13

8 0

3 years ago

PLZ HELP, WILL GIVE BRAINLIEST

guajiro [1.7K]

Answer:

x = C, 35

Step-by-step explanation:

This involves two steps. First, you have to know that all the angles of a triangle add up to 180. So the first thing we do is find the angle of the whole red part. 180 - 73 - 51 = 56. Then, we have that one of the angles near it is 21 and the other angle is x. To find x, we do 51 - 21 = 35. Therefore, 35 = x.

Thanks for brainliest! :D

6 0

3 years ago

A 52 foot ladder is set against the side of the house so that it reaches up 48 feet .if jevonte grabs the ladder at its base and

Vesnalui [34]

Answer:

Step-by-step explanation:

The way to approach this that makes the most sense to a student would be to find out how far from the house the ladder currently is, then add 3 feet to that and do the problem all over again. This is right triangle stuff...Pythagorean's Theorem in particular. The ladder is the hypotenuse, 52 feet long. The height of the rectangle is the distance the ladder is up the side o the house, 48 feet. We plug those into Pythagorean's Theorem and solve for the distance the ladder is from the house:

$52^2=48^2+x^2$ and

$2704=2304+x^2$ and

$x^2=400$ so

x = 20. Now if we add the 3 feet that the ladder was pulled away from house, the distance from the base of the ladder to the house is 23 feet, the ladder is still 52 feet long, but what's different is the height of the ladder up the side of the house, our new x:

$52^2=23^2+x^2$ and

$2704=529+x^2$ and

$2175=x^2$ so

x = 46.6 feet

6 0

3 years ago