Answer:
6 is the right answer I know cause I like science
The answer is; C
Conservation of matter in a reaction means that the mass of matter in the products is equal to the mass of the reactants. Energy/matter cannot be created or destroyed but converted from one form to another.
An expanding balloon with the increased evolution of gas is a good visible practical sign in the experiment on the conservation of matter in the reaction. As the magnesium disappears with an increased input of hydrochloric acid, the balloon gets bigger showing that more hydrogen is evolved from the reaction;
2HCL + Mg MgCl2 + H2
Answer:
![[SO_2Cl_2] = 0.09983 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%20%3D%200.09983%20M)
Explanation:
Write the balance chemical equation ,
![SO_2Cl_2((g) = SO_2(g) + Cl_2(g)](https://tex.z-dn.net/?f=SO_2Cl_2%28%28g%29%20%3D%20SO_2%28g%29%20%2B%20Cl_2%28g%29)
initial concenration of ![SO_2Cl_2((g) =0.1M](https://tex.z-dn.net/?f=SO_2Cl_2%28%28g%29%20%20%3D0.1M)
lets assume that degree of dissociation=![\alpha](https://tex.z-dn.net/?f=%5Calpha)
concenration of each component at equilibrium:
![[SO_2Cl_2] = 0.1-0.1\alpha](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%20%3D%200.1-0.1%5Calpha)
![[SO_2] = 0.1\alpha](https://tex.z-dn.net/?f=%5BSO_2%5D%20%3D%200.1%5Calpha)
![[Cl_2] = 0.1\alpha](https://tex.z-dn.net/?f=%5BCl_2%5D%20%3D%200.1%5Calpha)
![Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}](https://tex.z-dn.net/?f=Kc%20%3D%5Cfrac%7B0.1%5Calpha%20%5Ctimes%200.1%5Calpha%7D%7B0.1-0.1%5Calpha%7D)
![Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}](https://tex.z-dn.net/?f=Kc%20%3D%5Cfrac%7B0.1%5Calpha%20%5Ctimes%20%5Calpha%7D%7B1-%5Calpha%7D)
as
is very small then we can neglect ![1-\alpha](https://tex.z-dn.net/?f=1-%5Calpha)
therefore ,
![Kc ={0.1\alpha \times \alpha}](https://tex.z-dn.net/?f=Kc%20%3D%7B0.1%5Calpha%20%5Ctimes%20%5Calpha%7D)
![\alpha =\sqrt{\frac{Kc}{0.1}}](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Csqrt%7B%5Cfrac%7BKc%7D%7B0.1%7D%7D)
![\alpha = 1.73 \times 10^{-3}](https://tex.z-dn.net/?f=%5Calpha%20%3D%201.73%20%5Ctimes%2010%5E%7B-3%7D)
Eqilibrium concenration of ![[SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%20%3D%200.1-0.1%5Calpha%20%3D%200.1-0.1%5Ctimes%200.00173)
![[SO_2Cl_2] = 0.09983 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%20%3D%200.09983%20M)
You didn't give options but seedless vascular plants are plants that contain vascular tissue, but do not produce flowers or seeds so for example ferns and horsetails
Answer:
1) Pentane 2) 2-Pentene
Explanation:
Both molecules have five carbons so you will add thhe prefix "pent-" and the first molecule only has single bonds so it will end in "-ane" because is it an Alkane. The second hydrocarbon has a double bond; therefore, it's a Alkene resulting in the ending of "-ene". BUT the double bond is located on the second carbon; therefore you must add "2-" before the name.