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xxMikexx [17]
1 year ago
8

a solution was made by mixing sodium chloride () and water (). given that the mole fraction of water is 0.980 in the solution ob

tained from 64.9 g , calculate the mass of sodium chloride used.
Chemistry
1 answer:
Mnenie [13.5K]1 year ago
4 0

The mass of sodium chloride used <u>was 1.17 grams</u><u>.</u>

The mole fraction can be calculated by way of dividing the number of moles of 1 factor of an answer via the full variety of moles of all the additives of an answer. it is mentioned that the sum of the mole fraction of all the components inside the solution has to be the same as one.

mass  of NaCl given =  64.9 g

mole  = mass/molar mass

          = 64.9 / 58.5

          =<u> 1.109</u>

a mole fraction of water =  0.980

mole fraction of NaCl = 1 - 0.980

                                   = <u>0.02</u>

1 mole of NaCl =  58.5

mass of NaCl  = 58.5 × 0.02

                       =<u> 1.17 gram</u>

Mole Fraction describes the range of molecules contained within one aspect divided through the whole range of molecules in a given combination. it's miles quite beneficial whilst two reactive-natured components are mixed collectively.

Learn more about mole fraction here:-brainly.com/question/29111190

#SPJ4

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3 0
2 years ago
A 1.5 M solution of NaOH was made in a laboratory. If the solution made had a volume of 4.5 L, how many grams of NaOH were added
Crank

Answer:

270g

Explanation:

Given parameters:

Concentration of NaOH  = 1.5M

Volume  = 4.5L

Unknown

Mass of NaOH added  = ?

Solution:

To solve the problem, we need to find the number of moles of the NaOH first;

 Number of moles  = concentration x volume

 Number of moles  = 1.5 x 4.5  = 6.75mol  

Now;

  Mass  = Number of moles x molar mass

 Molar mass of NaOH  = 23 + 16 + 1  = 40g/mol

  Mass  = 6.75 x 40  = 270g

6 0
3 years ago
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