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Margarita [4]
3 years ago
11

Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no rea

ction occurs, write NO REACTION.
• sodium chloride and lead (II)
• acetate potassium sulfate and strontium iodide chromium (III)
• nitrate and sodium phosphate
Chemistry
2 answers:
Dima020 [189]3 years ago
4 0
<span>• sodium chloride and lead (II) acetate molecular equation.
</span>Pb(CH3COO)2 + 2 NaCl = PbCl2 + 2 CH3COONa

acetate potassium sulfate and strontium iodide chromium (III)  molecular equation
K2 SO4 (aq) + Sr I2 (aq) = 2 KI (aq) + Sr SO4 (s) 

• nitrate and sodium phosphate molecular equation
Cr(NO3)3 (aq) + Na3PO4 (aq) = 3 NaNO3 (aq) + CrPO4 (s)
Lady bird [3.3K]3 years ago
3 0

Answer: 2NaCl + Pb(C2H3O2))2 ==> 2NaC2H3O2 + PbCl2

K2SO4 + SrT2 ==> 2KI + SrSO4

Cr(NO3)3 + Na3PO4 ==> 3NaNO3 + CrPO4

Explanation:

PbCl2 is precipitated and is insoluble in the solution.

SrSO4 is precipitated and is insoluble in the solution.

CrPO4 is precipitated and is insoluble in the solution.

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4 years ago
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Tin (II) fluoride, formerly found in many kinds of toothpaste, is formed in this reaction: Sn (s) + 2HF (g) ——&gt; SnF2 (s) + H2
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1.34 L of HF

Explanation:

We have the following chemical reaction:

Sn (s) + 2 HF (g) → SnF₂ (s) + H₂ (g)

First we calculate the number of moles of SnF₂:

number of moles = mass / molecular weight

number of moles of SnF₂ = 5 / 157 = 0.03 moles

From the chemical reaction we see that 1 mole of SnF₂ are produced from 2 moles of SnF₂. This will mean that 0.03 moles of SnF₂ are produced from 0.06 moles of HF.

Now at standard temperature and pressure (STP) we can use the following formula to calculate the volume of HF:

number of moles = volume / 22.4 (L/mole)

volume of HF = number of moles × 22.4

volume of HF = 0.06 × 22.4 = 1.34 L

Learn more about:

problems with gases at STP

brainly.com/question/8857334

#learnwithBrainly

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