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Paraphin [41]
3 years ago
6

If 9^2x = 27/3^x+2, then find the value of x(a) 1/6(b) 1)5(c) -2/3(d) 1/8​

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

Step-by-step explanation:

We know, 9 to the power of 2 is 81

so it will be 81x

so its 81* a/b/c/d = 27/3 to the power of a/b/c/d +2

Solve for all answered!

goldenfox [79]3 years ago
3 0

Answer:

\textsf{Option (b) 1/5 is your correct answer.}\\

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{ {9}^{2x}  =  \frac{27}{ {3}^{x + 2} } } \\

\bf ➤\underline{To\: find-} \\

\textsf{the value of x = ?}

\bf➤ \underline{Solution-} \\

\textsf{Given expression,}\\

\sf{ {9}^{2x}  =  \frac{27}{ {3}^{x + 2} } } \\

\sf{ \implies \: {9}^{2x} \times  {3}^{x + 2}    = 27} \\

\sf{ \implies \:( {3}^{2}  {)}^{2x}   \times  {3}^{x + 2} =  {3}^{3}  } \\

\sf{ \implies \: {3}^{4x}  \times  {3}^{x + 2}   =  {3}^{3} } \\

\sf{ \implies \:  {3}^{4x + x + 2}  =  {3}^{3} } \\

\sf{ \implies \:  { \cancel3}^{5x + 2}  =  { \cancel3}^{3} } \\

\sf{ \implies \: }5x + 2 = 3 \\

\sf{ \implies \: 5x = 3 - 2} \\

\sf{ \implies \: 5x = 1} \\

\sf{ \implies \: x =  \frac{1}{5} } \\

\bf ➤\underline{Answer-} \\

\bf \underline{Hence, the\: value\: of \:x \: is \: \frac{1}{5}.} \\

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