The question is incomplete. The complete question is :
Two companies modeled their profits for one year.
- Company A used the function P(t)=1.8(1.4)^t to represent its monthly profit, P(t), in hundreds of dollars, after t months, where 0 < t ≤ 12.
-
Company B used the data in the table to write a linear model to represent its monthly profits.
Which statement describes the relationship between the profits, predicted be the models, of the two companies?
Solution :
For one year, the two companies A and B modeled their profits.
It is given that :
Company A uses function
in order to represent the monthly profit of the company in hundreds of dollars after a time
.
But the company B uses the data in the table in order to write the linear model to represent their monthly income.
We know the linear function is given by :

Here, m = slope of line
c = y-intercept
According to the data from the table , we see that the two points
and
lies on the line so that the slope of the line is represented by :

The point
passes through the given line.
∴ 



Therefore, the function will be 
So, at
,
the profit of the company A is 
= 6.91
the profit of the company A is 
= 20 - 10
= 10
Therefore,
, the profit of the company B is more than the profit of company A.
Now at
,
Profit of company A is 
= 102.05
Profit of company B is 

= 56
Therefore, the profit of company A is more that that of company B at the end of the year one.
Thus, company B had a greater profit for the fourth month and ended the year with the greater monthly profits than company A.
Option (B) is the correct answer.