Can someone please help me with this question?

2 = 3 − q what does 9 equal

IgorLugansk [536]

Step-by-step explanation:

2 = 3 - q

1 = (3 - q)×1/2

9 =(3 - q) ×1/2×9

9 = 27 - Q/2

8 0

3 years ago

Read 2 more answers

Determine whether these two ratios<br> form a proportion:<br> 8/10 and 24/30

galina1969 [7]

Hi there Moon,

The proportion you’re looking for would be 2/5, it is the smallest possible fraction

4 0

3 years ago

The intersection of two streets forms a parallelogram. One street is 40 feet wide. The height of the parallelogram formed is 25

snow_tiger [21]

Answer:

The area of the intersection is 1000 sq ft.

Step-by-step explanation:

It is given that,

The intersection of two streets forms a parallelogram. One street is 40 feet wide. The height of the parallelogram formed is 25 ft.

We need to find the area of the intersection.

It means the a parallelogram has a base of 40 feet and a height of 25 feet. Area of parallelogram is given by :

$A=b\times h\\\\A=40\times 25\\\\A=1000\ \text{feet}^2$

So, the area of the intersection is 1000 sq ft.

5 0

3 years ago

Read 2 more answers

The following series are geometric series or a sum of two geometric series. Determine whether each series converges or not. For

Sergeeva-Olga [200]

Answer:

Required solution gives series (a) divergent, (b) convergent, (c) divergent.

Step-by-step explanation:

(a) Given,

$\sum_{n\to 0}^{\infty}\frac{2^n}{9^{2n}+1}$

To applying limit comparison test, let $a_n=\frac{2^n}{9^{2n}+1}$ and $b_n=\frac{9^{2n}}{2^n}$ . Then,

$\lim_{n\to\infty} \frac{a_n}{b_n}=\lim_{n\to\infty}(1+\frac{1}{9^{2n}})=1>0$

Because of the existance of limit and the series $\frac{9^{2n}}{2^n}$ is divergent since $\frac{9^{2n}}{2^n}=(\frac{9^2}{2})^n$ where $\frac{81}{2}>1$ , given series is divergent.

(b) Given,

$\sum_{n\to 1}^{\infty}(\frac{7^n}{7^n+4})$

Again to apply limit comparison test let $a_n=\frac{7^n}{7^n+4}$ and $b_n=\frac{1}{7^n}$ we get,

$\lim_{n\to \infty}\frac{a_n}{b_n}=\frac{1}{7^n+4}=0$

Since $\lim_{n\to \infty} \frac{1}{7^n}=0$ is convergent, by comparison test, given series is convergent.

(c) Given,

$\sum_{n\to 1}^{\infty}\frac{5^n+2^n}{6^n}= \sum_{n\to 1}^{\infty}(\frac{5}{6})^n+\sum_{n\to 1}^{\infty}(\frac{1}{3})^n$ . Now applying Cauchy Root test on last two series, we will get,

\lim_{n\to \infty}|(\frac{5}{6})^n|^{\frac{1}{n}}=\frac{5}{6}=L_1
\lim_{n\to \infty}|(\frac{1}{3})^n|^{\frac{1}{n}}=\frac{1}{3}=L_2

Therefore,

$\lim_{n\to \infty}\frac{5^n+2^n}{6^n}=L_1+L_2=1.16>1$

Hence by Cauchy root test given series is divergent.

5 0

4 years ago

The circumference of circle P is 800 mm, the circumference of circle Q is 200 cm, and the circumference of circle R is 4 m. What

Lapatulllka [165]

Answer:

circle P has a circumference of 800mm which is equal to 80cm

circle Q is 200cm

circle R is 4m which is equal to 400cm

You will get the sum of the distances by placing the figures under one measurement that is meters

And so add the figures in cm(200+400+80) and get 680

Then convert this to meters and get 6.8m

Hence your answer is C

3 0

3 years ago