<span>The code goes like this
int temp;
temp = pos1; pos1 is assigned to temp.
pos1 = pos2; pos2 is assigned to pos1 and at this point temp is same as temp
pos2 = pos3; pos3 is assigned to pos2 and at this point temp is same as temp
pos3 = pos4; pos4 is assigned to pos3 and at this point pos4 is same as temp
pos4 = temp; pos4 is temp now and cycle rotate making pos4 getting pos1 value.</span>
<span>The square root of 1296 is 36.</span>
Total = 6x^2 and 2x
so
6x^2 + 2x = 2x (3x +1)
answer
A. 2x (3x +1)
Answer: the 57 the term is - 909
Step-by-step explanation:
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + d(n - 1)
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = - 13
d = - 29 - - 13 = - 45 - - 29 = - 16
n = 57
We want to determine the value of the 57th term, T57. Therefore,
T57 = - 13 - 16(57 - 1)
T57 = - 13 - 896
T57 = - 909