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Andru [333]
3 years ago
15

Find the 57th term of the arithmetic sequence -13, -29, -45, ...

Mathematics
2 answers:
valina [46]3 years ago
5 0

Answer: the 57 the term is - 909

Step-by-step explanation:

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = - 13

d = - 29 - - 13 = - 45 - - 29 = - 16

n = 57

We want to determine the value of the 57th term, T57. Therefore,

T57 = - 13 - 16(57 - 1)

T57 = - 13 - 896

T57 = - 909

lora16 [44]3 years ago
5 0
The answer is 57 and the term is -909
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<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

  • (6x+10°)
  • (x+17°)
  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

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