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zloy xaker [14]

3 years ago

5

What is 329*56 divided by 21

2 answers:

KonstantinChe [14]3 years ago

4 0

Answer:

The answer is 877.333333333

larisa86 [58]3 years ago

3 0

Answer:

877.333333...

Step-by-step explanation:

Hope this helps!

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What is the value of y when x= 2.5

liubo4ka [24]

Answer:

The value of y is unknown bas there is no equation

6 0

3 years ago

What is the square root of 1000/100000

Mrac [35]

Remember that $\sqrt{\frac{x}{y} }= \frac{ \sqrt{x} }{ \sqrt{y} }$ so
$\sqrt{\frac{1000}{100000} }= \frac{ \sqrt{1000} }{ \sqrt{100000} }$
find the individual square roots
$\frac{ \sqrt{1000} }{ \sqrt{100000} }$ = $\frac{ 10\sqrt{10} }{ 100\sqrt{10} } = \frac{10}{100} times \frac{ \sqrt{10} }{ \sqrt{10} } = \frac{10}{100} times 1= \frac{1}{10}$

answer is 1/10

7 0

3 years ago

Read 2 more answers

Aramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet, as shown in the figure.

bonufazy [111]

Answer:

The ratio of Tan B is

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

$\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}$

Step-by-step explanation:

In Right Angle Triangle ABC

angle C = 90°

AB = Ramp = 17 feet

BC =Horizontal distance = 15 feet

AC = Height from floor = 8 feet

To Find:

Ratio of Tan B = ?

Solution:

In Right Angle Triangle ABC By Tangent Identity we have

$\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}$

Substituting the given values we get

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

$\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}$

5 0

4 years ago

PLEASE HELP ASAP!!!!!

Akimi4 [234]

Answer:

Part A: 140

Step-by-step explanation:

Line ACE is a straight line meaning it equals 18 degrees. To find out what Angle CEF is you have to subtract 40 from 180. That gives you 140 degrees.

Hope its helpful!

3 0

3 years ago

STatiana [176]

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

The given equation is:

$3-k=\sqrt{3k+1}$

Square both sides of the equation

$(3-k)^2=3k+1$

Expand the left side of the equation above

$(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1$

Write the quadratic equation in standard form

$k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\$

Factor the quadratic equation

$(k-8)(k-1)=0$

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

Learn more here: brainly.com/question/25840704

8 0

3 years ago

Read 2 more answers