The total number of cookies baked by grandma = 96
Number of grandchildren = 8
As given, all cookies were evenly divided among 8 children, let us assume that everyone except Cindy got equal share. So on being divided equally, it becomes,
cookies per children.
But, as mentioned that Cindy received 'c' cookies less, so let us suppose Cindy received 'x' cookies.
Expression becomes: 
Hence, Cindy received 12-c cookies.
Answer:
8 ================================================================ D
i might be incompetent but at least I'm not impotent
Step-by-step explanation:
Answer:
Large books = 11
Small books = 6
Step-by-step explanation:
7x + 5y = 107
7x = 107 - 5y
x = 107/7 - 5y/7
5x + 7y = 97
5 (107/7 - 5y/7) + 7y = 97
535/7 - 25y/7 + 7y = 97
535/7 + 24y/7 = 97
535 + 24y = 679
24y = 679 - 535
y = 144/24 = 6: So x =
7x + 5(6) = 107
7x = 107-30
x = 77-7 = 11
Answer:
A
Step-by-step explanation:

Answer:
Matrix multiplication is not conmutative
Step-by-step explanation:
The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix
Let A with dimension mxn and B with dimension nxp represent two matrix
The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.
But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.
The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:
![A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11%26a12%5C%5Ca21%26a22%5Cend%7Barray%7D%5Cright%5D%5C%5CB%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%5C%5Cb21%26b22%5Cend%7Barray%7D%5Cright%5D%5C%5CAB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11b11%2Ba12b21%26a11b12%2Ba12b22%5C%5Ca21b11%2Ba22b21%26a21b12%2Ba22b22%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CBA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11a11%2Bb12a21%26b11a12%2Bb12a22%5C%5Cb21a11%2Bb22ba21%26b21a12%2Bb22a22%5Cend%7Barray%7D%5Cright%5D)
Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.