Your answer would be Water. :)
Agree because one interaction can affect many and or impact the ecosystem traumatically
Let us assign the
recessive allele for freckle to be f and
the dominant F. According to the statement, we deduce that ff = 0.04.
The frequency of the recessive f allele is, therefore, is
0.2 (square root of 0.04 ).
Hardy-Weinburg p + q = 1
P + 0.2 = 1; p = 1- 0.2 = 0.8
Therefore using the Hardy-Weinburg equation of a population
in equilibrium
P2+2pq+q2=1
Heterozygous individuals are;
2pq = 2*0.8*0.2 = 0.32
This is 32% of the population
Answer:
(B) The organism lives and replicates despite protease and DNase treatment, but the organism dies when treated with RNase.
Explanation:
DNA is the genetic material in present day organisms while some of the proteins serve as enzymes and catalyze the metabolic reactions.
An organism having RNA with the ability to serve as genetic material would not require DNA to survive. Likewise, if RNA molecules in these organisms also serve as the enzyme, proteins would not be required for survival.
Therefore, when treated with DNase and protease that digest the DNA and proteins respectively, these organisms would be able to survive. However, treatment with RNase enzymes that digest the RNA would kill them as RNA was their biocatalyst and genetic material.
Answer:
This process by which an unstable atomic nucleus loses energy by releasing radiation is called radioactive decay. The thing that makes this decay process so valuable for determining the age of an object is that each radioactive isotope decays at its own fixed rate, which is expressed in terms of its half-life.
Explanation:
