Hello
the line passes by A ( 0 ; -2) and B (5 ; 0) equation : y = ax+b
a is a slop : a = (yb - ya)/(xb -xa)
a = (0+2)/(5-0)
a =2/5
y = (2/5)x+b
if x=5 and y= 0
0 = (2/5)(5)+b
b= - 2
the equation is : y = (2/5)x-2
R-9s=2 add 9s to both sides
r=2+9s making 3r-3s=-10 become:
3(2+9s)-3s=-10 perform indicated multiplication on left side
6+27s-3s=-10 combine like terms on left side
6+24s=-10 subtract 6 from both sides
24s=-16 divide both sides by 24
s=-16/24
s=-2/3, making r-9s=2 become:
r-9(-2/3)=2 perform indicated multiplication on left side
r+6=2 subtract 6 from both sides
r=-4
So s= -2/3 and r= -4
Simplify the following:
k - 2 (k - (2 - k)) - 2
-(2 - k) = k - 2:
k - 2 (k + k - 2) - 2
Grouping like terms, k + k - 2 = (k + k) - 2:
k - 2 ((k + k) - 2) - 2
k + k = 2 k:
k - 2 (2 k - 2) - 2
-2 (2 k - 2) = 4 - 4 k:
k + 4 - 4 k - 2
Grouping like terms, k - 4 k - 2 + 4 = (4 - 2) + (k - 4 k):
(4 - 2) + (k - 4 k)
k - 4 k = -3 k:
-3 k + (4 - 2)
4 - 2 = 2:
Answer: 2 - 3 k
Answer:
X/-1 + Y/2 = 1
Step-by-step explanation:
25.69 + .75= $26.44
Hope this helps.
