Y = 28000-(8500*3)
8500 is the yearly deprecation value times 3 because it is 3 years
T\The answer would be 3 6/10, or 3.6.
Answer:
x=![\frac{16}{\sqrt[3]{2}+1 }](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B%5Csqrt%5B3%5D%7B2%7D%2B1%20%7D)
Step-by-step explanation:
Q= illumination
I = intensity
Q= I/d^2
Q_total = 
= 
now Q' = 0
⇒I
x=
[/tex]
x=
is the required point
One example is if you wanted to measure the height of a tall building. You'll need to measure the distance from where you're standing to the base of the building. You'll also need the angle of elevation. To get the angle of elevation, start by looking completely horizontal, then tilt upward until your eyeline reaches the top of the building. Once you have those two things (the side and angle) you can use the tangent ratio to find the height. This is because
tan(angle) = opposite/adjacent
where in this case
angle = angle of elevation
opposite = height of building
adjacent = distance from your position to the base of the building
It takes a bit of algebra, but the opposite side can be solved for. You'll most likely need a calculator to compute the tangent ratio.
yes it is greater than 2/5
