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Len [333]
3 years ago
14

Does anybody have any tips for calculating slopes in Algebra 1???

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

The equations are really hard, so if you can find a slope interpreter or something that might be helpful.

I find it easier to just count the up and across.

Step-by-step explanation:

You might be interested in
how many solutions does the equation 2(2x- 10)-8 =-2(14-3x) have?A.exactly one solution B. exactly two solutions C. no solution
Zarrin [17]

Answer: it has no solutions

Step-by-step explanation:

Factor then solve to find the complex solutions.

5 0
3 years ago
Find the missing factor 6s^2-7s-5=(3s-5)()
victus00 [196]
Answer: 2s + 1


Explanation:

1) Given expression: 6s² - 7s- 5 = (3s - 5) (        )

2) The missing factor (     ) is such that when it is multiplied by (3s - 5) the product is 6s² - 7s- 5.

3) Since the first term of the first factor starts with 3s, the first term of the second factor shall be 2s (since they have to yield 6s²). Then, you can write:

6s² - 7s- 5 = (3s - 5) (2s +    )

4) The second term of the missing factor is positive because the product (+)(-) = (-) which is the sign of the third term of the polynomial.

5) The second term is such that when multiplied by - 5 is equal to the last term of the polynomial (also - 5), so this second terms is +1.

And you get: 6s² - 7s- 5 = (3s - 5) (2s +  1)

6) You can expand, using distributive property to confirm the result:

(3s - 5) (2s +  1 ) =  (3s)(2s)  + (3s)(1) - (5)(2s) -(5)(1) =  6s² - 7s- 5, which confirms the result.
3 0
3 years ago
using a protractor and a ruler draw a right triangle with a side length of 5cm that is beetween the right angle and a 30 degree
Elza [17]

The Triangle will look in this way (Attached image)-

<h3>How do you draw a 30 degree angle with a protractor?</h3>

Step 1: Draw a line segment OQ.

Step 2: Place the center tip of the protractor at point O such that the protractor perfectly aligns with line AQ.

Step 3: Start from 'Q' on the protractor in the anti - clockwise direction and stop at 30. Mark it as point 'P'. If point 'Q' lies to the right of 'O', then start measuring clockwise and stop at 30.

Step 4: Now, place the protector at point Q, mark the point 'P' at 90, such that ∠OQP = 90.

Step 5: Join point 'P' with 'O'. ∠QOP=30° is the required 30 degree angle.

To learn more about triangles from the given link

brainly.com/question/9912231

#SPJ4

3 0
2 years ago
Solve by factoring:4x^6+4x^5-24^4=0
Len [333]

Answer:

you could only get to “4x^6+4x^5-331776=0” that would be the simpliest form

Step-by-step explanation:

6 0
3 years ago
Evaluate the following intervals<br>x^-4dx​
igor_vitrenko [27]

Answer:

simplified:

\frac{d}{x^3}

and Find the integral if that's what you also wanted:

-\frac{1}{3x^3} +3

8 0
3 years ago
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