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Alex_Xolod [135]
3 years ago
7

What is the range of the function g(x)=[x]+1

Mathematics
2 answers:
Lerok [7]3 years ago
6 0

<em>Assuming [x] means the closest integer to x</em>

Answer:

(-\infty, \infty)

Step-by-step explanation:

We can see that for any integer x, there will always be a [x], so there will always be a [x]+1. So, we don't need to worry about the domain impacting the range.

[x] can be any integer from -\infty to \infty, and as \infty+1=\infty(at least in terms of a function's range and domain), the range of [x]+1 is equal to the range of [x], which is (-\infty, \infty).

So, the answer is \boxed{(-\infty, \infty)} and we're done!

steposvetlana [31]3 years ago
3 0

Answer:

2

3

4

5

Step-by-step explanation:

g (1)=1+1=2

g (2)=2+1=3

g (3)=3+1=4

g(4)=4+1=5

range =2, 3, 4 ,5.......

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Solve the missing variable
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Answer:

110°

Step-by-step explanation:

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4 years ago
What is h(x)=x^(2)+2 find x if h(x)=6 please help me
zysi [14]

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its both positive or negative 2

Step-by-step explanation:

Y=x^(2)+2

*subtract the 2 on both sides: 6=x^(2)+2

*square root both sides: 4=x^2

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6 0
3 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
4 years ago
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