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slavikrds [6]
3 years ago
13

What is 9xy=1 in polar form

Mathematics
2 answers:
drek231 [11]3 years ago
3 0
<span>r=1/9cos(θ)sin(θ) Hope this helps!</span>
Elis [28]3 years ago
3 0
You can use x = r cosA y = r sin A
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Nathan needs to sell at least 75 t shirts to get a bonus he already has sold 15 red tye dye shirts and 23 solid blue ones how ma
AnnyKZ [126]

Red shirts and blue shirts equally count to his bonus, so he has 15 + 23 = 38 shirts sold at this moment. He needs to sell 75 shirts for the bonus. We subtract our goal from what he have; 75 - 38 = 37.


The strategy here: subtract the goal (75 shirts) from what you did to get to the goal (15 shirts and 23 shirts).


Nathan needs to sell 37 more shirts for the bonus. Hope this helps.

4 0
4 years ago
Read 2 more answers
Fine won't help me since I wrote long then here is short blah blah blah.......HELP ME BIT CONFUSED
Paul [167]
7/1×1/9

7×1=7
1×9=9

your answer is 7/9

hope this helped

4 0
3 years ago
Read 2 more answers
the ratio of girls to boys who participated in the Geography Bee was 5/4 there are there were 36 total students how many were bo
sammy [17]

suppose the number of boy is x ,so the number of girls is 5/4x,so the total number is 9/4x,we knew the number of total students is 36,so 36=9/4x,x is 16.

6 0
3 years ago
What is the different possible results from a probability model
Wewaii [24]
“Equally likely outcomes in probability.
In some sample spaces, it is reasonable to estimate or assume that all outcomes in the space are equally likely (that they occur with equal probability). For example, when tossing an ordinary coin, one typically assumes that the outcomes "head" and "tail" are equally likely to occur.”
5 0
4 years ago
Explain why the function is discontinuous at the given number
Blizzard [7]
For f to be continuous at x=5, we need to have

\displaystyle\lim_{x\to5}f(x)=f(5)

Note that x\to5 means that x\neq5, but that x is *approaching* 5. We're told that for x\neq5, we have

f(x)=\dfrac{x^2-5x}{x^2-25}

We can write

\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}

and the limit would be

\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)

and so f is discontinuous.
5 0
3 years ago
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