c - the molarity, n - the number of moles, V - the volume of the solution
First calculate the number of moles of AgNO₃ in the solution.
The volume is
.
The molarity:
.
The molarity is
0.016 mol/L.
Ethanol contains an alcohol group (-OH), which includes hydrogen bonding. Hydrogen bonding is stronger than other IMFs such as Van der Waals forces and Dipole-Dipole.
Ethene only has Van der Waals forces as it is an alkene with only C-H or C-C bonds. These means that the forces are not as strong.
Since ethanol contains hydrogen bonding, it will take a higher temperature in order to break these bonds, and thus results in a higher boiling point than ethene.
Answer:
Resistance
Explanation:
Resistance is the measure of the opposition of current in a circuit.
Answer:
n = 0.413moles (3 sig-figs).
Explanation:
From definition of molarity, solve for moles and substitute given data.
Molarity(M) = Moles Solute(n)/Volume of Solution in Liters(V)
M = n/V => n = M·V => 0.330moles/Liter x 1.25Liters = 0.4125moles ≅ 0.413moles (3 sig-figs).