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3 years ago

What are epimers? How are glucose and manose epimers? Please Help!

Chemistry

2 answers:

katrin2010 [14]3 years ago

4 0

Answer:

PLZ MARK ME BRIANLIEST I REALLY WANT IT PLZZZZZZ ISS GARIB KI DUA LAGEGI YARR PLZ

Explanation:

Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.

dybincka [34]3 years ago

3 0

Answer:

<h3>Epimers are carbohydrates which vary in one position for the placement of the -OH group</h3>

Explanation:

<h3>they have a specific type of stereoisomers which have multiple stereo center's but differ from one another, </h3><h3>they differ from each other by configuring at the c-2" atom . so, they are epimers </h3>

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How many grams is 5.4x10 to the 23 molecules of al2o3?

8090 [49]

Answer:

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

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3 years ago

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melamori03 [73]

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3 years ago

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17 Two substances in a mixture differ in density and particle size. These properties can be used to(1) separate the substances

belka [17]

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4 years ago

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Calculate the number of grams in 9.00 x 10²⁶ atoms of potassium.

shutvik [7]

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2 years ago

How much of glucose (C6H1206) is needed to make 1 L of a 1-M solution? Use details to support your answer.

Yakvenalex [24]

Answer:

200 g C₆H₁₂O₆

General Formulas and Concepts:

Chemistry - Solutions

Reading a Periodic Table
Using Dimensional Analysis
Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

1 M C₆H₁₂O₆

1 L of solution

Step 2: Identify Conversions

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

Step 3: Find moles of solute

1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L

x = 1 mol C₆H₁₂O₆

Step 4: Convert

$1 \ mol \ C_6H_{12}O_6(\frac{180.18 \ g \ C_6H_{12}O_6}{1 \ mol \ C_6H_{12}O_6} )$ = 180.18 g C₆H₁₂O₆

Step 5: Check

We are given 1 sig figs. Follow sig fig rules and round.

180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆

3 0

3 years ago