Answer:
Chloroform= limiting reactant
0.209mol of CCl4 is formed
And 32.186g of CCl4 is formed
Explanation:
The equation of reaction
CHCl3 + Cl2= CCl4 + HCl
From the equation 1 mol of
CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4
From the question
25g of CHCl3 really with Cl2
Molar mass of CHCl3= 119.5
Molar mass of Cl2 = 71
Hence moles of CHCl3= 25/119.5 = 0.209mol
Moles of Cl2 = 25/71 = 0.352mol
Hence CHCl3 is the limiting reactant
Since 1 mole of CHCl3 gave 1mol of CCl4
It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4
Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g
Answer:
Weight of boulder = 22,400 gram
Explanation:
Given:
Volume = 8,000 cm³
Density = 2.8
Find:
Weight of boulder
Computation:
Weight of boulder = Volume x Density
Weight of boulder = 8,000 x 2.8
Weight of boulder = 22,400 gram
Answer:
The new temperature will be 565.83 K.
Explanation:
Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.
In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

When an ideal gas goes from a state 1 to a state 2, it is true:

In this case:
- P1= 180 kPa
- T1= 291 K
- P2= 350 kPa
- T2= ?
Replacing:

Solving:

T2= 565.83 K
<u><em>The new temperature will be 565.83 K.</em></u>
D. Black holes
When a star dies out it explodes and causes a supernova and after a very long period of time the supernovas gasses vanish and the star can be visibly identified as a black hole!
Answer: The volume of given gas is 2.27 L.
Explanation:
Given: Mass = 3.54 g
Temperature =
= (25 + 273) K = 298 K
Pressure = 725 mm Hg (1 mm Hg = 0.00131579) = 0.95 atm
As moles is the mass of substance divided by its molar mass.
So, moles of argon (molar mass = 40 g/mol) is as follows.

Formula used to calculate the volume of given gas is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.

Thus, we can conclude that the volume of given gas is 2.27 L.