Letter A is the characteristic of all chemical change
Aldehyde is a group of organic compounds with the general form of RCHO. Oxidation of aldehyde can lead to the formation of the carboxylic acids, with the general form of RCO₂H.
With this oxidation, the typical reagents promoting the oxidation are chromic acids, chromate salts, permanganate, etc.
All of the energy from the reactants will be lost to the surroundings.The energy found in the reactants remains in the system, and the reactants also take energy from the
surroundings is true of energy in reactants during endothermic reaction.
<h3>What is Endothermic reaction?</h3>
Endothermic reaction is a reaction in thermochemistry where the reactants absorb heat from the surrounding to form the products.
In an endothermic reaction, the products have more energy than the reactants, that is they absorbed more energy. The reactants have less energy,that is they loss energy . Therefore, the change in enthalpy is positive, heat is absorbed from the surroundings during the reaction.
Therefore, All of the energy from the reactants will be lost to the surroundings.
The energy found in the reactants remains in the system, and the reactants also take energy from the
surroundings is true of energy in reactants during endothermic reaction.
For more details on endothermic reaction check the link below.
brainly.com/question/6506846
Answer:
2.05 x 10²⁴ molecules
Explanation:
The balanced equation for the chemical reaction is the following:
2 HCl + Mg → MgCl₂ + H₂
According to the equation, 2 moles of HCl are required to react with 1 mol of magnesium (Mg), so the moles of HCl required to react with 1.7 mol Mg are calculated as follows:
moles HCl = 1.7 mol Mg x 2 mol HCl/mol Mg = 3.4 mol HCl
We know that 1 mol of any compound is equal to 6.022 x 10²³ molecular entities, so we convert the moles of HCl to molecules as follows:
molecules HCl = 3.4 mol HCl x 6.022 x 10²³ molecules/1 mol = 2.05 x 10²⁴ molecules
Answer:
The rate constant for a second order reaction is
k = 0.51 dm-3 s-1.
Explanation:
In a regular second-order reaction the rate equation is given by v = k[A][B], if the reactant B concentration is constant then v = k[A][B] = k'[A], where k' the pseudo–first-order rate constant = k[B].
Also 1/|A| = Kt + 1/|Ao|
But Ao = 0.657 M and
A = 0.0981 M also
t = 17.0 s
Therefore
1/| 0.0981 M| =K × 17.0 s + 1/| 0.657 M|
→ 10.19/M = 17K + 1.52/M
10.19/M - 1.52/M = 8.67/M = 17K
K = 8.67M/17s = 0.51 dm-3 s-1.
k = 0.51 dm-3 s-1.
