Answer:
B: blank = blanks[:n] + letter + blanks[n+1:]
Explanation:
While I don't know what the different sections of this line of code does, I was able to find my answer by looking through the section of code below the videos and found this identical line. This is sometimes the best technique for finding answers to questions like this because it was rather hard to find otherwise. Hope this helps :)
Answer:
void print_popcorn_time(int bag_ounces){
if(bag_ounces < 3){
cout<<"Too small"<<endl;
}else if(bag_ounces > 10){
cout<<"Too large"<<endl;
}else{
cout<<(6 * bag_ounces)<<"seconds"<<endl;
}
}
Explanation:
The function is the block of the statement which performs the special task.
For checking the condition in the program, the if-else statement is used.
It can check the condition one or two but if we want to check the more than two different conditions then the continuous if-else statement is used.
syntax of continuous if else:
if(condition){
statement;
}else if(condition)
statement;
}else{
statement;
}
In the question, there are three conditions;
1. bag_ounces is less than 3
2. bag_ounces greater than 10
3. else part.
we put the condition in the above if-else statement and print the corresponding message.
it is called an attribute
