There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.
Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).
In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.
Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.
Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.
The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
1 * 12 = -40
12 = -40
Since its not possible for twelve to equal negative-forty, than there is no answer for this equation.
Answer:
m∠B = 
.
Step-by-step explanation:
Since the three sides of the triangle are given, then we apply cosine rule.
= 
+ 
- 2ac Cos B
But, a = 660 cm, b = 680 cm, and c = 100 cm.
So that;
= 
+ 
-2(660 x 100) Cos B
462400 = 435600 + 10000 - 132000 Cos B
462400 = 445600 - 132000 Cos B
132000 Cos B = 445600 - 462400
= -16800
Cos B = 
= -0.1273
B = 
-0.1273
=
Thus, measure of ∠B is .
Answer/Step-by-step explanation:
Yo, I think it might be the second choice!
