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anastassius [24]
3 years ago
5

Jaylen is picking berries. The number of blueberries he picks is 4 less than half the number of strawberries he picks. If Jaylen

picks x strawberries, select the expression that represents the number of blueberries he picks.
A. 2x + 4

B. x/4 +2

C. x/2 - 4

D. x/2 +4​

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0
The answer is:
C. x/2-4

Hope this helps!!
You might be interested in
How many minutes is it from 8:00am to 11:40am?
ollegr [7]

Answer:

220 minutes

Step-by-step explanation:

Find how many hours there are between the two times which is 3 hours then multiply 3 by 60 because there are 60 minutes in an hour

Since the time is 11:40 we also know 40 minutes have passed so add the two minutes

40+180=220

5 0
3 years ago
The weight of an apple is 150g, rounded to the nearest 5g. what is the lower bound and upper bound?
Aneli [31]

The lower bound is 147.5 and the upper bound is 152.5.

Given the weight of an apple 150 g rounded to the nearest 5g.

We have to find lower bound and upper bound.

Lower bound is an element less than or equal to all the elements in a given set.

Upper bound is an element greater than all the elements in a given set.

Lower bound= Number 1- (Number nearest to  which number 1 is rounded)/2

Upper bound=Number 1+(number nearest to which number 1 is rounded)/2

Weight of an apple =150 g

Lower bound=150-5/2

=150-2.5

=147.5

Upper bound=150+5/2

=150+2.5

=152.5

Hence the lower bound is 147.5 and upper bound is 152.5.

Learn more about lower and upper bounds at brainly.com/question/15408313

#SPJ4

4 0
2 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
Guys can u please help me out
sladkih [1.3K]

Answer:

-0.36a^5x^6b^6

Step-by-step explanation:

Ok first multiply the first two monomials:

-0.6a^3x^6b^3

Then multiply THAT with the OTHER monomial:

-0.36a^5x^6b^6

This should be the answer. Let me know if it's wrong.

6 0
3 years ago
Anyone know how to do this? Look at picture
wlad13 [49]
A) if they were the same function, they would have identical graphs ⇒ it's not A
B) it's flipped vertically, but it's not moved ⇒it's not B
C) it's flipped vertically, not horizontally ⇒ it's not C
So it must be D)

6 0
2 years ago
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