I think you count the squares in the middle or radius ?
Answer:
He must work for 115 hours to save at least $1900.
Step-by-step explanation:
The equation that you'll use is 65+16x=1900, with x being hours. I found the answer by using 65+16(115)=1905, which is the closest number you'll get before starting to use half hours and such.
Answer:
![300000= 100000 e^{0.12 t}](https://tex.z-dn.net/?f=%20300000%3D%20100000%20e%5E%7B0.12%20t%7D)
We divide both sides by 100000 and we got:
![3 = e^{0.12 t}](https://tex.z-dn.net/?f=%203%20%3D%20e%5E%7B0.12%20t%7D)
Now we can apply natural logs on both sides;
![ln(3) = 0.12 t](https://tex.z-dn.net/?f=%20ln%283%29%20%3D%200.12%20t)
And then the value of t would be:
![t = \frac{ln(3)}{0.12}= 9.16 years](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7Bln%283%29%7D%7B0.12%7D%3D%209.16%20years)
And rounded to the nearest tenth would be 9.2 years.
Step-by-step explanation:
For this case since we know that the interest is compounded continuously, then we can use the following formula:
![A =P e^{rt}](https://tex.z-dn.net/?f=A%20%3DP%20e%5E%7Brt%7D)
Where A is the future value, P the present value , r the rate of interest in fraction and t the number of years.
For this case we know that P = 100000 and r =0.12 we want to triplicate this amount and that means
and we want to find the value for t.
![300000= 100000 e^{0.12 t}](https://tex.z-dn.net/?f=%20300000%3D%20100000%20e%5E%7B0.12%20t%7D)
We divide both sides by 100000 and we got:
![3 = e^{0.12 t}](https://tex.z-dn.net/?f=%203%20%3D%20e%5E%7B0.12%20t%7D)
Now we can apply natural logs on both sides;
![ln(3) = 0.12 t](https://tex.z-dn.net/?f=%20ln%283%29%20%3D%200.12%20t)
And then the value of t would be:
![t = \frac{ln(3)}{0.12}= 9.16 years](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7Bln%283%29%7D%7B0.12%7D%3D%209.16%20years)
And rounded to the nearest tenth would be 9.2 years.
y = abˣ
20 = ab¹
20 = ab
b b
20/b = a
y = abˣ
4 = (20/b)b²
4 = 20b
20 20
¹/₅ = b
y = abˣ
20 = ¹/₅b¹
20 = ¹/₅b
¹/₅ ¹/₅
100 = b
y = abˣ
y = 100(0.2)ˣ
Answer:
<h2>
64 cm²</h2>
Step-by-step explanation:
given:
the scale from a square park to a drawing of the park is 5 m to 1 cm
the actual park has an area of 1,600 m²
find:
what is the area of the drawing of the park
solution:
drawing scale is 5m : 1cm
<u>1,600 m² </u> = <u> 5² m² </u>
x 1² cm²
cross multiply:
5² m² x = 1600 m² (1 cm²)
x =<u> 1600 m² </u>
5² m²
x = 64 cm²
therefore, the area of a square park in the drawing is 64 cm²