

<em><u>Solution:</u></em>
<em><u>We have to find the inequalities that are true</u></em>
<em><u>Option 1</u></em>

0.6 is not less than 0
Thus this inequality is not true
<em><u>Option 2</u></em>

0.667 is greater than 0.5
Thus this inequality is true
<em><u>Option 3</u></em>

0.818 is less than 1
Thus this inequality is true
<em><u>Option 4</u></em>

0.5 = 0.5
Thus the above inequality is not true
For this case we have:
Let a function of the form 
By definition, to graph
, where
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that 
So, if the black graph is given by
, the red graph is given by: 
Answer:

Option A
Answer:
n=4
Step-by-step explanation:
Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]
Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:
\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]
=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]
=> \[(8-n)*(4-n) =n*(n-4)*3\]
=> \[n-8 =3n\]
=> \[2n =8\]
=> n = 4
Start with

Separate the variables:

Integrate both parts:

Which implies

Solving for y:

Since
is itself a constant, let's rename it
.
Fix the additive constant imposing the condition:

So, the solution is

Answer:
The slope is undefined
Step-by-step explanation:
When graphed, the two points form a vertical line, since we can't divide the slope by zero thw slope is considered as undefined