All categories

4 years ago

$111.1 to the nearest $5

Mathematics

1 answer:

Vlad [161]4 years ago

3 0

$111.1 to the nearest $5 is $110

You might be interested in

The graph of a cosine function is shown. Which two points on the midline of the function are separated by a distance of one peri

Ray Of Light [21]

Answer: (pi/8, 1) and (5*pi/8, 1)

Step-by-step explanation:

First, the midline is a horizontal line that cuts the graph in two halves.

In this case, we can see that the maximum of the function is y = 2.5, and the minimum is y = -0.5

The difference is:

Diff = (2.5 - (-0.5)) = 3

If we subtract half of the difference (3/2 = 1.5) to the maximum, we get the midline.

Then:

midline: y = 2.5 - (3/2) = 1

the midline is the line y = 1

Now, a period T is such that:

Sin(x) = Sin(x + T)

Two points that are in the midline and that are separated by a period will be two points on the line y = 1, and that are in corresponding parts of the graph.

Here the two points are, counting from left to right, the third and the 11th.

(both of them are in the line y = -1 and in the negative slope part).

The points are:

(pi/8, 1) and (5*pi/8, 1)

6 0

3 years ago

Read 2 more answers

A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen

serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

$P=\frac{7}{579}=0.121$

b) The probability that both are defective is given by:

$P=\frac{8}{580}*\frac{7}{579}= 0.000167$

c) The probability that both are acceptable is given by:

$P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726$

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

$P=\frac{6}{578}}= 0.0104$

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

$P=\frac{7}{578}= 0.01211$

f) The probability that all three are defective is given by:

$P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731$

7 0

4 years ago

Is 10s equal one thousands

OLga [1]

Ten times ten equals one hundred, if that's what you are asking for.

5 0

3 years ago

Can i get some help with this?

liberstina [14]

Answer:

Look at the image, pls give brainliest!

Step-by-step explanation:

7 0

3 years ago

Which of these could change a taxpayer's adjusted gross

KiRa [710]

Answer:

$Student~loan~interest~pay$

Step-by-step explanation:

$That~should~be~the~answer~to~your~question.$

5 0

3 years ago