

An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airport is 7 kilometers. What is the angle of depression from the airplane to the airport? (Write the answer to the nearest degree.)


✞ Step 1 ✞: Identify what is asked in the problem.
❒ The angle of depression from the airplane to the airport.
✞ Step 2 ✞: Use appropriate trigonometric ratio to solve the problem.
❒ Since the two legs of the right triangle are part of the problem, hence we use tangent ratio:

✞ Step 3 ✞: Solution and interpretation.





Hence, the angle of depression from the airplane to the airport is approximately 36°.


For this question, you must use the Pythagorean theorem.
a^2 + b^2 = c^2
In this situation c=16 and a=6
First do 16^2. This equals 256
Second do 6^2. This equals 36
Now, subtract 36 from 256 and fond the square root.
Your answer should be 14.8
For this case we have to by definition:
1 kg equals 1000 grams
Shark 1:
405 kg and 68 grams

Thus, shark 1 weighs 405,068 grams.
Shark 2:
324 kg and 75 grams

Thus, shark 2 weighs 324,075 grams.
Subtracting we have:

Thus, shark 1 weighs 80,993 grams more than the second.
Answer:
Shark 1 weighs 80,993 grams more than the second.
Answer:
the percent is 18
Step-by-step explanation: