55% of a number is 25 so divide 25 by .55 then the answer is 45.45
Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test
Formula : 
Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
For the answer to the questions above,
A) Parrots are following a Geometric Progression of 15% increase.
20(1.15), 20(1.15)², 20(1.15)³,
Function = 20(1.15)^n Where n is at the end of year, n =1, 2, 3, ..
Snakes are increasing by 4.
28, 32, 36,....
Function = 24 + 4n n = number of end year, n =1, 2, 3,...
<span>B) After 10 years: </span>
Parrot = 20(1.15)¹⁰ = 80.91115471
Snakes = 24 + 4(10) = 64
<span>C) After what time they are the same: </span>
We use trial and error:
Test: n 20(1.15^n) (24 + 4n)
1 23 28
2 26.45 32
<span> 3 30.41 36 </span>
4 34.98 40
5 40.23 44
6 46.26 48
7 53.20 52
8 61.18 56
9 70.36 60
After year 7, the Parrots increases far more.
<span>At year 7 they are roughly the same.</span>
Direct variation is y=kx, inverse variation is y=k/x....
-5y=-2x divide both sides by -5
y=2.5x
So this is a direct variation with a constant of 2.5
