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Stels [109]
3 years ago
11

A certain drug is made from only two ingredients: compound A and compound B. There are 5 milliliters of compound A used for ever

y 7 milliliters of compound B. If a chemist wants to make 1188 milliliters of the drug, how many milliliters of compound A is needed?
Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0

Step-by-step explanation:

Subtract 7ml from 5 ml and you will find your answer

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Fractions equivalent to -2/-3
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2/3, 4/6, -4/-6... gtg sorry if you needed more

Step-by-step explanation:

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What value will make the equation true
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pick the value that when you solve it, you get the correct answer

Step-by-step explanation:

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3 years ago
Which of the following is NOT a monomial?<br> a. x-4<br> b. 22xy<br> c. 3<br> d. -11x
qwelly [4]
Answer is (a)
its a binomial
not a monomial
7 0
3 years ago
A right cone has a surface area of 440 square inches and a radius of 7 inches. Find its slant height.
EastWind [94]

Answer:

Surface Area of right cone  

               =\pi r(r+\sqrt{h^2 + r^2}

440 = \pi *7*(7+\sqrt{h^2+7^2})\\\\440 = 7\pi (7 + \sqrt{h^2+7^2})\\\\\frac{440}{7\pi } = 7 + \sqrt{h^2+49}\\\\\frac{440}{7\pi } - 7 = \sqrt{h^2+49}\\\\\frac{440-49\pi}{7\pi} =\sqrt{h^2+49}\\\\

\frac{286.062}{21.99} =\sqrt{h^2+49}\\\\13.0087= \sqrt{h^2+49}\\\\(13.0087)^2 = (\sqrt{h^2+49})^2\\\\169.227 = h^2 +49\\\\169.227 - 49 =h^2\\\\120.227 = h^2\\\\h = \sqrt{120.227}  = 10.96in

7 0
3 years ago
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
4 years ago
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