For these questions it's asking you to substitute the value into the equation.
For example question 5 says,
26= y-9;y=35
basically it's saying if y=35, is the equation correct or not.
In this case: 26= 35 -9 is correct.
So your answer is true.
Hope this helps Xx
Hmm, one way is this
there's 500 times 0.10 or 50 grams of salt in the water
if we want to make 50 grams=4% of everything, how much water do we need to add
50=4% of all
50=0.04 of all
divide both sides by 0.04
1250=all
so
500+what=1250
minus 500 both sides
what=750
750 grams of water
Use both!
You want to minimize <em>P</em>, so differentiate <em>P</em> with respect to <em>x</em> and set the derivative equal to 0 and solve for any critical points.
<em>P</em> = 8/<em>x</em> + 2<em>x</em>
d<em>P</em>/d<em>x</em> = -8/<em>x</em>² + 2 = 0
8/<em>x</em>² = 2
<em>x</em>² = 8/2 = 4
<em>x</em> = ± √4 = ± 2
You can then use the second derivative to determine the concavity of <em>P</em>, and its sign at a given critical point decides whether it is a minimum or a maximum.
We have
d²<em>P</em>/d<em>x</em>² = 16/<em>x</em>³
When <em>x</em> = -2, the second derivative is negative, which means there's a relative maximum here.
When <em>x</em> = 2, the second derivative is positive, which means there's a relative minimum here.
So, <em>P</em> has a relative maximum value of 8/(-2) + 2(-2) = -8 when <em>x</em> = -2.