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yaroslaw [1]
3 years ago
8

Solve these equations)

Mathematics
2 answers:
tatuchka [14]3 years ago
8 0

Answer:

1. c=-2

2. 0=12 no solution

3. x=4

4. r=3/2

Step-by-step explanation:

Svetlanka [38]3 years ago
8 0

Answer:

1) 9c-3c= -8-4

6c=-12

c=-12/6

c=-2

2) 3×5x-3×2-6x=3×3x+3×2

15x-6-6x=9x+6

15x-6x-8x=6-6

15x-14x=0

x=0

3)-x+7x=24

6x=24

x=24/6

x=4

4) -2r-1/2×-2=-2

-2r+1=-2

-2r=-2-1

-2r=-3

r=-3/-2

r=3/2

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Samantha puts an initial $500 into a savings account. The account has a 4% annual compound interest rate. What is the function t
Licemer1 [7]
I use a bit of a different looking formula.

A(t)=P(1+r/n)^nt

P=amount of money. (500)
r= rate (in decimal. 4%=0.04)
n=number of times per year (1 in this problem)
t=amount of time. (5 years)

Plugged in it looks like this:

A(t)=500 (1+ 0.04/1)^1x5

Then I put it into my calculator like this:

0.04/1+ 0.04

Then add one to the above answer:

0.04+1=1.04

Then raise the above answer to the 1x5:

1.04^5=1.2166......

Then multiply the above answer by 500:

1.2166.... x 500=608.3264512

She has $608 after 5 years.

Hope this helps, let me know if you have any questions.
5 0
2 years ago
Henry gross pay is $4000 a month. If he saves $500 of his pay, what percent of his pay does he save?
Makovka662 [10]

Answer:

12.5%

Step-by-step explanation:

big brain

7 0
2 years ago
Find a number such that 10 less than two thirds the number is one fourth the number
Ivan

Answer:

the number is 24

Step-by-step explanation:

10 less than two thirds the number is one fourth the number

Let the unknown number be x

two third of the number is \frac{2}{3} x

10 less than two third the number becomes

\frac{2}{3}x-10

one fourth the number becomes \frac{1}{4}x

10 less than two thirds the number is one fourth the number

\frac{2}{3}x-10=\frac{1}{4}x

We need to solve for x

LCD is 3*4 = 12

Multiply the whole equation by 12

\frac{2*12}{3}x-10*12=\frac{1*12}{4}x

8x - 120 = 3x

add 120 on both sides

8x = 3x + 120

Subtract 3x on both sides

5x = 120

divide by 5 on both sides

x= 24




3 0
3 years ago
Factor completely: 3x^3+33x^2+54x=0
kap26 [50]

Answer:

3(x + 9)(x + 2)x = 0

Step-by-step explanation:

xv1 = −9

xv2 = −2

xv3 = 0

7 0
2 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
1 year ago
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