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Karo-lina-s [1.5K]
2 years ago
9

Adding decimals 2.134 + 345.04 = ?

Mathematics
2 answers:
iVinArrow [24]2 years ago
8 0
<h2>Hello! :D</h2>

We must add 2.134+345.04.

The Answer to your question is

<h2>347.174</h2>

Now, was it helpful?

⃝    Yes, it was! I will mark you Brainliest!! Thank you for your help!!

⃝   No, it wasn't helpful at all! :(

Hope it was helpful!

#Keep_On_Gaining_Knowledge

nadezda [96]2 years ago
3 0

Answer: 347.175

Step-by-step explanation: line up the desimal up it will help

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A trapezoid has an area of 329 square feet. If the bases are 30 feet and 17 feet, what is the height of the trapezoid in feet? F
ExtremeBDS [4]

Answer:

The correct option is C.  14 ft

Step-by-step explanation:

To calculate the height, we will follow the steps below;

Formula is given to be:  h = 2A / b1 +b2

where h = height of the trapezoid   b1 and b2 are the bases of the trapezoid    and A is the area of the trapezoid

From the question given;

Area A =329 feet²      b1 = 30 feet    b2 =17 feet  

We can now proceed to insert the values into the formula

h = 2A / b1 +b2

h= 2(329)  / 30 + 17

h = 658 /47

h=14 feet

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2 years ago
Find the greatest common factor of numbers using prime factorization 32 and 90
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the greatest common factor of 32 and 90 is 2

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Julian wants her rectangular garden to cover an AREA of 180 square feet what bare the LENGTHS AND WIDTHS of two possible rectang
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Read 2 more answers
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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