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Karo-lina-s [1.5K]
3 years ago
9

Adding decimals 2.134 + 345.04 = ?

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0
<h2>Hello! :D</h2>

We must add 2.134+345.04.

The Answer to your question is

<h2>347.174</h2>

Now, was it helpful?

⃝    Yes, it was! I will mark you Brainliest!! Thank you for your help!!

⃝   No, it wasn't helpful at all! :(

Hope it was helpful!

#Keep_On_Gaining_Knowledge

nadezda [96]3 years ago
3 0

Answer: 347.175

Step-by-step explanation: line up the desimal up it will help

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What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)
lozanna [386]

Answer: x=4

Step-by-step explanation:

1.5(x+4)-3=(x-2)

1.5x+6)-3=4.5x-9

1.5x+3=4.5x-9

      +9          +9

1.5x+12=4.5x

divide 1.5x and 4.5

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/3    /3

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5 0
3 years ago
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If a varies directly as b and a=3 when b=12, what is the value of a when b=18?
Zepler [3.9K]

Answer:

a is proportional to b

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k is proportionality constant

k =a/b =3/12 =1/4

k=1/4 = a/b=a/18

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If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

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The distance from 1st to 3rd base is roughly 127.2792 feet.

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2 years ago
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An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

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Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

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2 years ago
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