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Inessa05 [86]
3 years ago
11

What is the cube root of 216x^9y^8

Mathematics
2 answers:
exis [7]3 years ago
8 0
<span>cube root of 216x^9y^8

(</span>216x^9y^8)^(1/3)

216^(1/3) = 6

9/3 = 3

8/3 = 2 2/3

(216x^9y^8)^(1/3) = 6 x^3 y^2 y^(2/3)
romanna [79]3 years ago
7 0
Hello,
Please, see the attached file.
Thanks.

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A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
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Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

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Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

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So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

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Therefore, The expected winnings for a person buying 1 ticket is -0.2.

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