We know, Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 27³
v = 4/3 * 3.14 * 19,683
v = 82406.16 feet³
In short, Your Answer would be Option B
Hope this helps!
Given hollow cubical box of side 0.30 m=3 dM
volume V=3^3=27 dm^3 = 27 L
Weight of box
= weight of (fresh) water (1 kg/L) displaced
= V/3 = 9 L of water = 9 kg
When water is filled so that the total weight of water equals the weight of volume of box, the top rim of the box will be at water level.
Remaining volume = 27-9=18L
height of 18L of water when water rushes in
= 18/(3^2) = 2 dm (=0.2m)
Answer:
-2+5*2= -2+10/4
You get 8/4 which is 2
Step-by-step explanation:
Option a:
sin A for the triangle is 
.
Solution:
The given triangle is a right triangle.
The adjacent side to angle A is AC.
The opposite side to angle A is BC.
Hypotenuse is AB.
AC = 8, BC = 6 and AB = 10.
Using trigonometric ratio formulas,
Divide both numerator and denominator by 2, we get
Hence sin A for the triangle is .
Option a is the correct answer.
