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Sav [38]
3 years ago
5

Can someone help me 4k-7+2h=7

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

the answer is 4k+2h=14 the andwer

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Tolong bikin hari ini terakhir di kirim ​
statuscvo [17]

Answer:

try the answer D

Step-by-step explanation:

5 0
3 years ago
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In the wheel of woohoo game I'm taking a chance on a spinner with 20 outcomes if it lands on an even number I'll win a prize How
Aloiza [94]

Answer:  The chance here to win is 50%.


Step-by-step explanation:   You are taking a chance on a spinner with 20 outcomes. So, we will be considering natural numbers from 1 to 20.

And also, you will a prize if you land on an even number, so we will calculate the probability of getting an even number.

From 1 to 20, there are 10 odd numbers and 10 even numbers out of total 20 numbers.

Let us define the following events -

A = event of getting an even number

and

B = event of getting an odd number.

So, n(A) = 10  and  n(B) = 10.

So, the probability of getting an even number is given by

p(A)=\dfrac{n(A)}{n(A)+n(B)}=\dfrac{10}{10+10}=\dfrac{10}{20}=0.5=50\%.

Thus, the required chance of winning a prize is 50%.



4 0
3 years ago
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HELP ME!!
inysia [295]

Answer:

y intercept (0,-2) x intercept (3,0)

Step-by-step explanation:

first we have to solve for y.

2x-3y=6

step 1 subtract 2x from each side

-3y=-2x+6

step 2 divide each side by -3

y=2/3x-2

now I am going to graph this to make it easier for you

5 0
3 years ago
The smallest unit of size in the list below is the
Neko [114]
D.) Nanometer is the smallest among your options.

It is equal to 10^-9

Hope this helps!
5 0
3 years ago
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Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that \mu = 8, \sigma = 1.1

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

n = 5 means that s = \frac{1.1}{\sqrt{5}} = 0.4919

This probability is the pvalue of Z when X = 9.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{9.3 - 8}{0.4919}

Z = 2.64

Z = 2.64 has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

n = 6 means that s = \frac{1.1}{\sqrt{6}} = 0.4491

This probability is 1 subtracted by the pvalue of Z when X = 9. So

Z = \frac{X - \mu}{s}

Z = \frac{9 - 8}{0.4491}

Z = 2.23

Z = 2.23 has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

8 0
3 years ago
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