Answer:
A.
Step-by-step explanation:
Answer:
f(x inv)=-1/2x-3
Step-by-step explanation:
You pretty much just have to flip all the numbers to fractions and all the positives to negatives.
Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
The answer will be D 15m+2n
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
