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masha68 [24]
3 years ago
5

An object is thrown from a platform. Its height (in meters), x seconds after launch, is modeled by h (x) = -5 (x + 1) (x -9)

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.

x + 1 = 0 so

x = -1

x - 9 = 0 so

x = 9

We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).

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the length of a rectangle is 4a + 5, the width of the same rectangle is 2a -3 if the perimeter of the rectangle is 76 what is th
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Answer:

Here

perimeter=76

length =4a+5

breadth=2a-3

we know,

perimeter=2(length+breadth)

76=2(4a+5+2a-3)

76=2(7a+2)

76=14a+4

76-4=14a

72=14a

72÷14=a

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Answer:

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The parameters given are;

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Therefore, since the number soldiers calling out the number 3 are 1 in 3 from the left and 1 in 3 from the right, we split the soldiers into 2 groups of 1000, with one group calling from left and the other group calling from the right;

The number of 3s in called out in the first group from the left is therefore;

1000/3 = 333.33 which is 333 soldiers  or from the 3rd soldier to the 999th soldier

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Answer:

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